If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3k^2-15k+11=0
a = 3; b = -15; c = +11;
Δ = b2-4ac
Δ = -152-4·3·11
Δ = 93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{93}}{2*3}=\frac{15-\sqrt{93}}{6} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{93}}{2*3}=\frac{15+\sqrt{93}}{6} $
| ((2c+2.5))0.08+3=13.80 | | x+64=120 | | s3+6=9 | | (−9)+p=12 | | -30=6-4x | | 7z+1/9=8z+4/9 | | -9=1/3x-8 | | 2v=42 | | x/10-5=17/20 | | 4.7+10m=6.91 | | 3n+7n=99 | | s3+ 6= 9 | | (z+4)/(z+7)+(z/4)=(2z+11)/(z+7) | | -3+1+2x=-2x-5 | | 94x=11*3*x | | (12x-8)+40=180 | | 2(x+2)^2-128=0 | | m4+4=7 | | x/9-6=17/18 | | m4+ 4= 7 | | 30=2a+50 | | 2(x+2)^2-57=71 | | 0.4x+0.9x=0.8x-0.3 | | 4(2×5)=g | | r2+7=10 | | -4=1/3z+2 | | r2+ 7= 10 | | x^2+10x+9=16 | | -2g+-4=-8 | | (x-1)(x-4)(2x+3)=0 | | -x+√4x+36=1 | | 5/2x+5=20 |